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Question
Solution

Mary is a teacher in a middle school and she has a table seat storing students' names and their corresponding seat ids.

The column id is continuous increment.

Mary wants to change seats for the adjacent students.

Can you write a SQL query to output the result for Mary?

+---------+---------+
|    id   | student |
+---------+---------+
|    1    | Abbot   |
|    2    | Doris   |
|    3    | Emerson |
|    4    | Green   |
|    5    | Jeames  |
+---------+---------+

For the sample input, the output is:

+---------+---------+
|    id   | student |
+---------+---------+
|    1    | Doris   |
|    2    | Abbot   |
|    3    | Green   |
|    4    | Emerson |
|    5    | Jeames  |
+---------+---------+

Note:
If the number of students is odd, there is no need to change the last one's seat.

Solution
- Approach I: Using flow control statement CASE [Accepted]
- Approach II: Using bit manipulation and COALESCE() [Accepted]
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Solution

Approach I: Using flow control statement `CASE` [Accepted]

Algorithm

For students with odd id, the new id is (id+1) after switch unless it is the last seat. And for students with even id, the new id is (id-1). In order to know how many seats in total, we can use a subquery:

SELECT\n    COUNT(*) AS counts\nFROM\n    seat\n

Then, we can use the CASE statement and MOD() function to alter the seat id of each student.

MySQL

SELECT\n    (CASE\n        WHEN MOD(id, 2) != 0 AND counts != id THEN id + 1\n        WHEN MOD(id, 2) != 0 AND counts = id THEN id\n        ELSE id - 1\n    END) AS id,\n    student\nFROM\n    seat,\n    (SELECT\n        COUNT(*) AS counts\n    FROM\n        seat) AS seat_counts\nORDER BY id ASC;\n

Approach II: Using bit manipulation and `COALESCE()` [Accepted]

Algorithm

Bit manipulation expression (id+1)^1-1 can calculate the new id after switch.

SELECT id, (id+1)^1-1, student FROM seat;\n

| id | (id+1)^1-1 | student |\n|----|------------|---------|\n| 1  | 2          | Abbot   |\n| 2  | 1          | Doris   |\n| 3  | 4          | Emerson |\n| 4  | 3          | Green   |\n| 5  | 6          | Jeames  |\n

Then, we can make a temp table and join seat with this table like below.

SELECT\n    *\nFROM\n    seat s1\n        LEFT JOIN\n    seat s2 ON (s1.id+1)^1-1 = s2.id\nORDER BY s1.id;\n

| id | student | id | student |\n|----|---------|----|---------|\n| 1  | Abbot   | 2  | Doris   |\n| 2  | Doris   | 1  | Abbot   |\n| 3  | Emerson | 4  | Green   |\n| 4  | Green   | 3  | Emerson |\n| 5  | Jeames  |    |         |\n

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Note:The first two columns are from s1 and the last two are from s2.
\n

At last, we can output s1.id and s2.student. However, the s2.student is NULL for seat id \'5\' but s1.student is right. Thus, we we can use function COALESCE() to generate the correct output for the last record.

MySQL

SELECT\n    s1.id, COALESCE(s2.student, s1.student) AS student\nFROM\n    seat s1\n        LEFT JOIN\n    seat s2 ON ((s1.id + 1) ^ 1) - 1 = s2.id\nORDER BY s1.id;\n

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Note: This solution comes from @FANGXIAOFANG.
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626. Exchange Seats

Solution

Approach I: Using flow control statement CASE [Accepted]

Approach II: Using bit manipulation and COALESCE() [Accepted]

Approach I: Using flow control statement `CASE` [Accepted]

Approach II: Using bit manipulation and `COALESCE()` [Accepted]